Reef Chemistry Question of the Day #88 Baking Soda 1

Randy Holmes-Farley

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Reef Chemistry Question of the Day #88

A stock solution is made by dissolving 8.401 grams of baking soda (sodium bicarbonate; molecular weight = 84.01 g/mole) into enough pure freshwater at 25° C to make 1 L total volume. This solution has a pH of 8.300 and an alkalinity of 100.00 meq/L (~280 dKH). 1.000 mL of this solution is added to 99.000 mL of natural seawater (pH 8.200; alkalinity = 2.500 meq/L or 7.00 dKH). The alkalinity of the final solution is closest to:


A. 3.500 meq/L (9.80 dKH)
B. 3.475 meq/L (9.73 dKH)
C. 2.515 meq/L (7.04 dKH)
D. 2.500 meq/L (7.00 dKH)

Good luck!




















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tonizzy22

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Answer is B ((1mL×100meq/L)+(99mL×2.5meq/L))/100mL=3.475meq/L or ((1mL×280dKH)+(99mL×7dKH))/100mL= 9.73dKH
 

Skydvr

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I agree with Tonizz's answer and rationale.
 

reefins

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Ya i'm down with Tonizz's answer too.. nailed it!
 

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