Reef Chemistry Joke of the Day #8

[Randy Holmes-Farley]

You are proudly test filling your new aquarium with water for the first time.

After carrying buckets for a hour, you take a break and whine to your spouse:

"The dang thing is still half empty."

Ever helpful, she replies:

"No it isn't, it's half full!"

Meanwhile, your daughter, who is a budding reef chemist, announces:

"You are both wrong. It's____________________"

Fill in the blank.


Happy Reefing


Last joke:

Reef Chemistry Joke of the Day #7

Why are ammonia and soda ash the easiest chemicals to teach reefers about? No hints today. Previous joke: https://www.reef2reef.com/threads/reef-chemistry-joke-of-the-day-6.845831/

www.reef2reef.com

 

[Garf]

Full, 50% liquid, 50% gas.

 

[Righteous]

I must have a darks sense of humor…. I was going to go with “it’s leaking!”

 

[Miami Reef]

I must have a darks sense of humor…. I was going to go with “it’s leaking!”

Me too!

 

[Garf]

Wheras I have no sense of humour

 

[Miami Reef]

Wheras I have no sense of humour

Your answer was good! I think it’s correct.

 

[BostonReefer300]

It's at equilibrium?
I'm not even sure why I'm contributing. If my daughter found out I'm following reef chemistry joke threads, that would be the final straw in the "embarrassing Dad" judgment.

 

[Samandar]

As a Chemist the answer " it is at equilibrium" is right .
Hi Mr Holmes
But I have a problem,
Newly I have calculated the necessity of cacl2 and Na2CO3 for my new tank. I wrote the following formula
CaCl2(aq) +Na2CO3 (aq) <---> CaCO3(s) +2NaCl(aq)
So as you see, for each mol of cacl2 we need only one mol Na2CO3. On the other hand for 147 gr cacl2 we need only 106 gr Na2CO3. Is it right? Or I have missed something.

CaCl2 is dihydrate.
(CaCl2-2H2O) with mol weight 147 gr.
(Na2Co3) with mol weight 106 gr.

 

[Randy Holmes-Farley]

I must have a darks sense of humor…. I was going to go with “it’s leaking!”

lol

Nice.

 

[Randy Holmes-Farley]

As a Chemist the answer " it is at equilibrium" is right .
Hi Mr Holmes
But I have a problem,
Newly I have calculated the necessity of cacl2 and Na2CO3 for my new tank. I wrote the following formula
CaCl2(aq) +Na2CO3 (aq) <---> CaCO3(s) +2NaCl(aq)
So as you see, for each mol of cacl2 we need only one mol Na2CO3. On the other hand for 147 gr cacl2 we need only 106 gr Na2CO3. Is it right? Or I have missed something.

CaCl2 is dihydrate.
(CaCl2-2H2O) with mol weight 147 gr.
(Na2Co3) with mol weight 106 gr.

Already replied here:

Two part solutions

Hi Mr Holmes I have followed you since 2010. Newly I have calculated the necessity of cacl2 and Na2CO3 for my new tank. I wrote the following formula CaCl2(aq) +Na2CO3 (aq) CaCO3(s) +2NaCl(aq) So as you see, for each mol of cacl2 we need only one mol Na2CO3. On the other hand for 147 gr cacl2...

www.reef2reef.com

 

[Miami Reef]

lol

Nice.

Where’s the answer?

 

[Randy Holmes-Farley]

Where’s the answer?

Patience....

 

[Miami Reef]

Patience....

Randy called me out. ;Sorry

 

[Dkeller_nc]

The answer is: "The tank is over-specified". At least, that's the way us engineers would answer.

 

[Randy Holmes-Farley]

Full, 50% liquid, 50% gas.

Correct!


You are proudly test filling your new aquarium with water for the first time.

After carrying buckets for a hour, you take a break and whine to your spouse:

"The dang thing is still half empty."

Ever helpful, she replies:

"No it isn't, it's half full!"

Meanwhile, your daughter, who is a budding reef chemist, announces:

"You are both wrong. It's completely full: half with water and half with air! Aren't you glad the quarter million you spent sending me to college wasn't wasted?"

Happy Reefing!