DIY various trace elements formula to make specific concentration

speedinc

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Hi all, I was wondering if anyone out there could help me figure out a formula to create various trace elements with specific concentration. i.e. how much of the traces I need to add in grams/milli grams to 50ml of RODI water. I'll list the trace elements I have below on hand. Thanks for the help in advance.

Potassium Iodide (10,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Potassium Iodide 99.5% CAS 7681-11-0

Potassium Chloride (100,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Potassium Chloride 99.5% CAS 7447-40-7

Sodium Fluoride (30,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Sodium Fluoride 99% CAS 7681-49-4

Strontium (50,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Strontium Chloride hexahydrate CAS 10476-85-4

Boron (50,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Boric Acid 99.5% CAS 10035-06-0

Bromide (50,000ppm) - 50ml in a dropper bottle
Trace Element I have on hand: Sodium Bromide 99.5% CAS 7647-15-6
 

Randy Holmes-Farley

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There’s a sticky thread in this topic:

 
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speedinc

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There’s a sticky thread in this topic:


Hi Randy, thanks for the link. I did go through it but I needed to make specific concentration as per my post i.e. 10,000ppm - 100,000ppm. None of the sticky thread link provided a formula to mix to specific concentration.
 
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speedinc

speedinc

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Why do you need those concentrations?

Hi Randy, it's to make the solution below etc.... I use their 3 part methods and figured I could source my own traces and save a lot of $$ in the long run by making my own traces.

 

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Well, OK. It's just a lot of extra work to create a different recipe for everyone who wants a different potency and a different volume created just for them when any potency and volume will work equally well.

Also, your solutions are quite concentrated and will have a density above 1 g/mL, making mg/L not equal to ppm. I'm not sure if you company you are trying to mimic made that adjustment or not.


Potassium iodine is 76% iodide by weight. 1 gram provides 760 mg. So 1 g in 6.6 g water gives 760 mg/7.6 grams total = 100,000 mg/kg = ppm. To make it using 50 g water, use 7.6 g KI.

Potassium chloride is 52.3% potassium by weight. 1 gram provides 523 mg K. So 1 g in 4.2 g (mL) water gives 523 mg/5.2 grams total = 100,000 mg/kg K = ppm. To make with 50 ml water, use 11.9 g KCl.

Sodium fluoride is 45% fluoride by weight. 1 gram provides 450 mg F. So 1 g in 14 g (mL) water gives 450 mg/15 grams total = 30,000 mg/kg F = ppm. To make with 50 ml water, use 3.6 g NaF.

Strontium Chloride hexahydrate is 32.8% strontium by weight. 1 g provides 328 mg, so 1 g in 2.3 g water (3.3 g total) gives 328 mg/3.3 g total = 100,000 ppm. For 50 mL, use 21.7 g.

you cannot make boric acid this strong. You need borax or other material. Boric acid solubility limit is 57 g/L, and since it is only 175 boron by weight, the max at 25 deg C is only 9.9 g/L boron = 10,000 ppm.

Sodium bromide is 77.7% bromide by weight. 1 gram provides 777 mg Br. So 1 g in 14.6 g (mL) water gives 777 mg/ 15.6 grams total = 50,000 mg/kg Br = ppm. To make with 50 ml water, use 3.2 g NaBr.
 
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speedinc

speedinc

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Well, OK. It's just a lot of extra work to create a different recipe for everyone who wants a different potency and a different volume created just for them when any potency and volume will work equally well.

Also, your solutions are quite concentrated and will have a density above 1 g/mL, making mg/L not equal to ppm. I'm not sure if you company you are trying to mimic made that adjustment or not.


Potassium iodine is 76% iodide by weight. 1 gram provides 760 mg. So 1 g in 6.6 g water gives 760 mg/7.6 grams total = 100,000 mg/kg = ppm. To make it using 50 g water, use 7.6 g KI.

Potassium chloride is 52.3% potassium by weight. 1 gram provides 523 mg K. So 1 g in 4.2 g (mL) water gives 523 mg/5.2 grams total = 100,000 mg/kg K = ppm. To make with 50 ml water, use 11.9 g KCl.

Sodium fluoride is 45% fluoride by weight. 1 gram provides 450 mg F. So 1 g in 14 g (mL) water gives 450 mg/15 grams total = 30,000 mg/kg F = ppm. To make with 50 ml water, use 3.6 g NaF.

Strontium Chloride hexahydrate is 32.8% strontium by weight. 1 g provides 328 mg, so 1 g in 2.3 g water (3.3 g total) gives 328 mg/3.3 g total = 100,000 ppm. For 50 mL, use 21.7 g.

you cannot make boric acid this strong. You need borax or other material. Boric acid solubility limit is 57 g/L, and since it is only 175 boron by weight, the max at 25 deg C is only 9.9 g/L boron = 10,000 ppm.

Sodium bromide is 77.7% bromide by weight. 1 gram provides 777 mg Br. So 1 g in 14.6 g (mL) water gives 777 mg/ 15.6 grams total = 50,000 mg/kg Br = ppm. To make with 50 ml water, use 3.2 g NaBr.

Hi Randy,

Thank you for taking your time to provide the formula above. I did some google search and found someone had calculated something similar and I've came up with a spreadsheet of my own. I think some of your above calculation's concentration were incorrectly placed thus providing a very high concentration! Can you please verify my calculation below is correct?

NameDescriptionminor or major element(1)formulamolar mass (gram/mol)atomic mass of desired elementdesired element in chemical by percentageTrace Concentration to make (ppm)1L Bottle (grams to add)50ml Bottle (grams to add)
BoronBoric Acid AR 99.5% 500g CAS 10035-06-0
15401-500g
H3BO361.8310.8117.48%50,000285.985198914.30
BromideSodium Bromide 99.5% LR CAS 647-15-6
46208-100g
NaBr102.8979.90437477.66%50,00064.383208863.22
PotassiumPotassium Chloride AR 100g
41701-100g
KCI74.5539.152.45%100,000190.66496169.53
IodinePotassium Iodide 99.5% AR 100g 43001-100gKI166126.976.45%10,00013.081166270.65
FluorideSodium Fluoride AR 99% CAS 7681-49-4NaF41.991945.25%30,00066.33.32
StrontiumStrontium Chloride AR 100g hexahydrate CAS 10476-85-4
51001-100g
SrCl2 · 6H2O266.6287.6232.86%50,000152.14562897.61
 

Randy Holmes-Farley

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I think my calculations are correct, but differ from yours mostly because I made them to ppm, which is what you asked for, while your spreadsheet seems to be making them in mg/L.

The more concentrated a solution is, the more those differ, and some of these are very concentrated.

Two other comments:

1. The boron recipe fails for the solubility reason I stated.

2. My KI recipe and Strontium recipe are both for 100,000 ppm, as indicated. I misread what you wanted. If you want 10,000 ppm and 50,000 ppm, respectively , you would use a lot less, obviously. use your calculation, but it is mg/L, not ppm.
 

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