Hummm... I see what you are saying, but the 10K resistor there will be in parallel with the already existing led and 4K7 resistor from the board witch will lower even more the resistance.
Let's calculate more or less:
1 / 1000 ohm (new resistor) + 1 / 470 ohm (one from the board plus the led, not counting with led value since will be near 1 ohm or a lot lower) = 1 / 0.003 = 319 ohm rounded final value
If I remember correctly from my old DIY driver design a simple circuit like this I had it working with my first DIY led lamps using a direct PWM from an Arduino:
Then I connected the lamp power supply positive straight to the lamp and control the negative trough this circuit.
I had 4 lamps, 2 for blue light and 2 for white so the four exits on the chematiq two for each color channel, just ignore the MOSFET name, since that one is not a 5V logic level one, that one has a RDS(on) for @10V. ; )
Let's calculate more or less:
1 / 1000 ohm (new resistor) + 1 / 470 ohm (one from the board plus the led, not counting with led value since will be near 1 ohm or a lot lower) = 1 / 0.003 = 319 ohm rounded final value
If I remember correctly from my old DIY driver design a simple circuit like this I had it working with my first DIY led lamps using a direct PWM from an Arduino:
Then I connected the lamp power supply positive straight to the lamp and control the negative trough this circuit.
I had 4 lamps, 2 for blue light and 2 for white so the four exits on the chematiq two for each color channel, just ignore the MOSFET name, since that one is not a 5V logic level one, that one has a RDS(on) for @10V. ; )