Two part recipe, exact amount of weight

[badstraw]

Hey Dr. @Randy Holmes-Farley!

I'm having a hard time trying to measure the exact amount that I need to dose with the two part recipes, specifically Im talking about the magnesium part.

Alkalinity: 594 grams of baking soda in 1 gallon of water or 3785 ml
Calcium: 500 grams of calcium chloride dihydrate in 1 gallon of water or 3785 ml

Magnesium part:
5 cups > magnesium sulfate, would that be 1182 grams?
3 cups > magnesium chloride hexahydrate, would that be 709 grams?
Both dissolved in 1 gallon of water or 3785 ml.

I really appreciate any help you can provide.

 

[Randy Holmes-Farley Verified Community Expert]

The magnesium part is designed for 64 ounces of Epsom salt when that is used alone, and the final concentration should be 47,000 ppm.

It is close enough to use 3 x 64/8 = 24 ounces of the chloride (680 grams) and 5 x 64/8 = 40 ounces (1134 g). :)

 

[Randy Holmes-Farley Verified Community Expert]

Bear in mind that built into the magnesium part is some guesswork about exactly how much magnesium is used by the organisms in your tank when they use the alk and calcium parts, so exact measurement isn't going to be required.

 

[badstraw]

Thank you for the clarifications. I appreciate it.

Now, if I don't plan to use recipe #1 and instead I go with recipe #2, I will have the same results and no effect on the PH, right?

I would love to hear your opinion about this recipe:

Calcium : Dissolve 220,5 grams of calcium chloride dihydrate to make 33.8 oz of total solution, 2 tsp for each 26 gallons will raise calcium levels 6 ppm.

Alkalinity: Dissolve in 84.5 oz of water: 200.7 grams of baking soda and 31,6 grams of soda ash (Na2CO3), 5 tsp for each 26 gallons will raise alkalinity 0,85 dKH.

Part 3 (third solution) Dissolve in 33.8 oz :

Epsom salt (MgSO4-7H2O) 43.89 g
Magnesium chloride hexahydrate (MgCl2-6H2O) 36.83 g
Potassium chloride(KCl) 4.53 g
Potassium bromide (KBr) 0.623 g
Strontium chloride hexahydrate (SrCl2-6H2O) 0.1942 g
boric acid (H3BO3) 0,1618 g
potassium iodide (KI) 0,0045

It would be insane to weigh chemicals like potassium iodide, boric acid or potassium bromide etc, so it could be done multiplying it by 100 times :

.1618 x 100 = 16.18 grams to dissolve it in 33.08 oz

Then we would just take one hundredth part of that solution = 2 tsp, to pour it in the third solution, so then we will have to do the same for the remaining chemicals.

So the correct dosing would be 1/ 2.5 / 1 to maintain ionic balance.

So if you add 2 tsp of calcium, then you would have to add 5 tsp of alkalinity and 2 tsp of the "third solution", I hope that makes sense.