DIY Additive

greenwind82

Community Member
View Badges
Joined
Nov 6, 2013
Messages
48
Reaction score
13
Rating - 0%
0   0   0
Hello Randy,

This is my first time making my own additive solution. After reading your different postings, here are what I am about to purchase & solution proportions. Can you please check if the following are correct? Will dosing these adding more Sodium ( or Sulfur in case of Manganese) to the tank? Do you have any recommendation on the dissolve amount? Should I store them in glass bottle or plastic bottle? Thanks so much for your help!

1. Boron
https://www.amazon.com/gp/product/B00IB2MN86/ref=ox_sc_act_title_3?smid=A224H40ZI0MLC0&psc=1

Boron is 11.3% by weight. Dissolve 1 gram in 1000 mL RO/Di. Concentration is 113 mg/L or 0.113 mg/mL. Adding 1 mL per 100 gallons boosts Boron by 0.113 mg/378 L = 0.00029 mg/L.

2. Bromine
https://www.amazon.com/Sodium-Bromi...qid=1541350690&sr=8-9&keywords=sodium+bromide

Bromine is 77.7% by weight. Dissolve 1 gram in 1000 mL RO/Di. Concentration is 777 mg/L or 0.777 mg/mL. Adding 1 mL per 100 gallons boosts Bromine by 0.777 mg/378 L = 0.00205 mg/L.

3.Manganese
https://www.amazon.com/gp/product/B00SXZV2BA/ref=ox_sc_act_title_5?smid=A224H40ZI0MLC0&psc=1

Manganese is 32% by weight. Dissolve 1 gram in 1000 mL RO/Di. Concentration is 320 mg/L or 0.32 mg/mL. Adding 1 mL per 100 gallons boosts Manganese by 0.32 mg/378 L = 0.00084 mg/L.

4.Molybdate
https://www.amazon.com/gp/product/B00L21B9DS/ref=ox_sc_saved_title_1?smid=A23XB2IU56PL57&psc=1

Molybdate is 39.5% by weight. Dissolve 1 gram in 1000 mL RO/Di. Concentration is 395 mg/L or 0.395 mg/mL. Adding 1 mL per 100 gallons boosts Molybdate is by 0.395 mg/378 L = 0.00104 mg/L.
 

Randy Holmes-Farley

Reef Chemist
View Badges
Joined
Sep 5, 2014
Messages
67,529
Reaction score
63,977
Location
Arlington, Massachusetts, United States
Rating - 0%
0   0   0
Sodium borate decahydrate weighs 381.4 grams per mole.

1. Boron weighs 10.8 grams per mole.

This, it is 10/8/381.4 * 100% = 2.8%. So the initial percentage assumption is incorrect.

Bromide is correct.
 
OP
OP
greenwind82

greenwind82

Community Member
View Badges
Joined
Nov 6, 2013
Messages
48
Reaction score
13
Rating - 0%
0   0   0
Sodium borate decahydrate weighs 381.4 grams per mole.

1. Boron weighs 10.8 grams per mole.

This, it is 10/8/381.4 * 100% = 2.8%. So the initial percentage assumption is incorrect.

Bromide is correct.

Thanks for your response @Randy Holmes-Farley but please correct me if I am wrong, the formula for Sodium Borate Decahydrate is Na2B4O7.10H2O, there are 4 Boron in there so shouldn’t it be 10.8 / 381.4 * 4 * 100% = 11.3%?
 

Randy Holmes-Farley

Reef Chemist
View Badges
Joined
Sep 5, 2014
Messages
67,529
Reaction score
63,977
Location
Arlington, Massachusetts, United States
Rating - 0%
0   0   0
Thanks for your response @Randy Holmes-Farley but please correct me if I am wrong, the formula for Sodium Borate Decahydrate is Na2B4O7.10H2O, there are 4 Boron in there so shouldn’t it be 10.8 / 381.4 * 4 * 100% = 11.3%?

Oh, sorry, yes. That's exactly why I do not like checking folks math when I'm rushing through the forum questions. :)
 
OP
OP
greenwind82

greenwind82

Community Member
View Badges
Joined
Nov 6, 2013
Messages
48
Reaction score
13
Rating - 0%
0   0   0
@Randy Holmes-Farley can you tell me what safety precautions should I be taken when making any supplement solutions? I was doing research on making Fluoride solution from Sodium Fluoride and according to Wikipedia it has GHS rating as danger. Thanks
 

Form or function: Do you consider your rock work to be art or the platform for your coral?

  • Primarily art focused.

    Votes: 20 7.9%
  • Primarily a platform for coral.

    Votes: 44 17.4%
  • A bit of each - both art and a platform.

    Votes: 171 67.6%
  • Neither.

    Votes: 12 4.7%
  • Other.

    Votes: 6 2.4%
Back
Top