DIY Radeon clone?

[oreo54]

4

Running 4 in series AND controlling each of 7 channels individually is going to be expensive.
56v blue
56V white
56V violet
28V green
28V UV
18.4v Red
10.4v Yellow

7 Meanwell LCM-60U drivers.
2-72V @700mA

LCM-U Series Mean Well 40~60W Multi-Output CC LED Drivers

$255...

3 in 1 DIMMING
0~10VDC, PWM, or resistance signal dimming function

2 of these would work if you combine some of the channels and run 2 "sets" of pucks.
(1) 28v
(2) 28v
(3) 28v

(4)14v
(4)14v
=28V

(5)18.4v
(5) 10.4
= 28.8V

combining red and yellow is probably fine
green and UV is a bit odd but as is there would be no choice
36V power supply 200W or better to run BOTH of the arrays.
So all 4.

 

[danielch2008]

i did understand this volts and calculares ….

1) 28v
(2) 28v
(3) 28v

(4)14v
(4)14v
=28V

(5)18.4v
(5) 10.4

 

[danielch2008]

i did understand this volts and calculares ….

1) 28v
(2) 28v
(3) 28v

(4)14v
(4)14v
=28V

(5)18.4v
(5) 10

I did not understand

 

[danielch2008]

Running 4 in series AND controlling each of 7 channels individually is going to be expensive.
56v blue
56V white
56V violet
28V green
28V UV
18.4v Red
10.4v Yellow

7 Meanwell LCM-60U drivers.
2-72V @700mA

LCM-U Series Mean Well 40~60W Multi-Output CC LED Drivers

$255...



2 of these would work if you combine some of the channels and run 2 "sets" of pucks.
(1) 28v
(2) 28v
(3) 28v

(4)14v
(4)14v
=28V

(5)18.4v
(5) 10.4
= 28.8V

combining red and yellow is probably fine
green and UV is a bit odd but as is there would be no choice
36V power supply 200W or better to run BOTH of the arrays.
So all 4.

Not 7 Channel. Are 8 channels

 

[oreo54]

I did not understand

Every led has a particular voltage that it has at a particular amperage.
Take the 4 blues. Each led has 3.5V across it.
Run 4 in series +..-..+...- ect you add the voltage up or multiply
4 x 3.5 = 14V
Put 4 sets of 4 in series.. that is 14 x 4 = 56V
That is the voltage needed to run all 16 leds in series.
And say for the blue channel with 16 leds now in series and at 700mA (your choice) that string is
56V x .700A = 39.2 Watts


I took the MAX voltage listed as a safety feature.


Repeat for every other color..

 

[danielch2008]

Every led has a particular voltage that it has at a particular amperage.
Take the 4 blues. Each led has 3.5V across it.
Run 4 in series +..-..+...- ect you add the voltage up or multiply
4 x 3.5 = 14V
Put 4 sets of 4 in series.. that is 14 x 4 = 56V
That is the voltage needed to run all 16 leds in series.
And say for the blue channel with 16 leds now in series and at 700mA (your choice) that string is
56V x .700A = 39.2 Watts


I took the MAX voltage listed as a safety feature.


Repeat for every other color..

Perfect. When you say you're going to get the high voltage, is the solution to combine the colors? Where did you get the voltage of each Led? 3.5v of blue

 

[danielch2008]

I saw voltage 14 / 4 = 3.5v

 

[oreo54]

Perfect. When you say you're going to get the high voltage, is the solution to combine the colors? Where did you get the voltage of each Led? 3.5v of blue

The voltage is off the data sheet.Like the max voltage for the white channel on one puck is 14V
There are 4 white leds per board.. in series.
14/4 = 3.5

OR use this table and the diagram..

 

[oreo54]

I saw voltage 14 / 4 = 3.5v

Yea 14 volts across 4 leds.. = 3.5v/LED
At 700mA
+(3.5)-+(3.5)-+(3.5)-+(3.5)-
In REAL life the voltage changes by the amount of current and a few other things like heat.. It is not a set in stone number.

 

[danielch2008]

But then I didn't understand something.... I have a 56v source, will I only be able to light only the blue Leds? In other words, each font for a color?

 

[oreo54]

But then I didn't understand something.... I have a 56v source, will I only be able to light only the blue Leds? In other words, each font for a color?

Well you need one DRIVER per string.
Like I said before .. if you really want to wire all 4 pucks in series with each channel being separate my current only way to do this is with these:
Meanwell LCM-60U.

You need 48-56V for the blue ect.
Less voltage for the other channels

The DRIVER will change the voltage till is SEES say 700mA Could be anywhere between 48-56V for the blue ect


If you use LDD's you need a power supply with 51 to 59V
And LDDS won't survive like 59V

2~52VDC MAX

 

[danielch2008]

Is it better to use the LDDs or this board to put all 4 disks with only one source?

 

[danielch2008]

This board or LDDs to all 4 in series

 

[oreo54]

This board or LDDs to all 4 in series

No, won't work.
3 in series is the maximum.

48v for the board which will only output like 44v.
Ldd 56v which will only output 52v


MAJOR CORRECTION TO PAST POSTS':
Somewhere I " lost" a channel.
The one chart skipped the rb apparently

There are eight.
188-ish total watts at 700mA

 

[oreo54]

Snip

 

[danielch2008]

Mesmo com os 52v que vão sobrar dos LDDs, os 4 não vão funcionar?

 

[danielch2008]

Even with the 52v that will be left over from the LDDs, the 4 won't work?

 

[oreo54]

Even with the 52v that will be left over from the LDDs, the 4 won't work?

The voltage may or may not be enough.
There is no way of knowing without trying it in the real world.

The spec sheet can't really be trusted but it lists 12-13v @700 mA
12 x 4 = 48 V
13 x 4 = 52 V
14 x. 4 = 56 V

Could be any of those or none of those..
It's just a possible range.


Looks like the worst would be you wouldn't get full power out of one, some, or all of the larger ones.

So 56v ps 8 ldd's, 1 per color, and you yet don't have a way to dim them.

 

[danielch2008]

If I remove the white channel and put all 4 in series, will I be able to work on the 56v source and with that Leds controller?

 

[danielch2008]

Another question.... As I am exchanging all my luminaires for this Leds board, I would like to know if there is a way to adapt my maxspect razor 180w by placing three of these Led boards.