Sochting Oxydator Help

[atoll]

Thank you. I googled the 6:1 ratio as you suggested and most conversion charts I found pretty much said the same thing. This ratio was too high for the H202% I was shooting for. What seems to be consistent across the different sites is the following information:

1:33 ratio is 3.03%

1:16.7 ratio is 5.99%

I will start out with a 1:33 ratio for the nem tank if you think this is more on track.
Suggestions for the 180 gal as a starting point?

BTW, I tried to find the fb community @atoll mentioned earlier in this thread but my searches have not turned up anything. Any idea what the group is called?

Thanks! I'll wait to hear back from you before I dilute the H202, just to be on the safe side. Thank you for your help!

Try Oxydator User Group as I changed the name to reflect the broader group of aquarists.

 

[Sashaka]

Try Oxydator User Group as I changed the name to reflect the broader group of aquarists.

@atoll
How does the dilution scale I found sound to you?
1:33 ratio = 3.03% and 1:16.7 ratio =5.99%
Is the plan to start out with a 1:33 ratio for the nem tank Ok?
Suggestions for the 180 gal as a starting point?

And thank you! I was able to locate the fb group with this name.

 

[SDK]

I just sent a join request as well...

 

[atoll]

Approved botb above.
I just put 2 parts RO to 1 part 12% hydrogen peroxide to get 9% ... well I think it is but Sashaka yours sounds more scientific [emoji848]

 

[Sashaka]

I just sent a join request as well...

Thanks! I'm reading the "files" in another open tab as we speak.

 

[Sashaka]

Approved botb above.
I just put 2 parts RO to 1 part 12% hydrogen peroxide to get 9% ... well I think it is but Sashaka yours sounds more scientific

According to the chart at https://www.essind.com/carpet-care/dilution-charts-and-conversion-tables/
1:2 = 33%.

I'm so confused. It's all coming back to me! I remember why I never got around to ordering the H2O2 last year. Trying to figure out how to convert to the correct strength of 3% or 6% is a nightmare for me! Ahhhhh! I've been at this for hours. Please save me! What am I doing wrong?

 

[JonJ]

Approved botb above.
I just put 2 parts RO to 1 part 12% hydrogen peroxide to get 9% ... well I think it is but Sashaka yours sounds more scientific [emoji848]

Not sure your math is correct. Either that or I’m doing it wrong . Mixing 2 parts water to 1 part H2O2 would be 3 parts total. 12% divided by 3= 4%

I use 2 oxydators in my RSR 750 and really like them. They keep the water crystal clear!

I use 35% peroxide mixed 3 to 1 for an 8.75% mix. I found the chart above that I used to determine my dilution.

 

[Sashaka]

Not sure your math is correct. Either that or I’m doing it wrong . Mixing 2 parts water to 1 part H2O2 would be 3 parts total. 12% divided by 3= 4%

I use 2 oxydators in my RSR 750 and really like them. They keep the water crystal clear!

I use 35% peroxide mixed 3 to 1 for an 8.75% mix. I found the chart above that I used to determine my dilution.

Thank you...thank you...thank you! Did I remember to tell you THANK YOU! Wait, I'm confused again. Isn't 1:1 ratio 50%...Oh! I think I final get it. It's not out of 100; it's out of 35! That's what I've been doing wrong!

 

[atoll]

Not sure your math is correct. Either that or I’m doing it wrong . Mixing 2 parts water to 1 part H2O2 would be 3 parts total. 12% divided by 3= 4%

I use 2 oxydators in my RSR 750 and really like them. They keep the water crystal clear!

I use 35% peroxide mixed 3 to 1 for an 8.75% mix. I found the chart above that I used to determine my dilution.

Sorry I meant 2 parts 12% peroxide to 1 part RO. [emoji53]

 

[JonJ]

Sorry I meant 2 parts 12% peroxide to 1 part RO. [emoji53]

That will make 4% h2O2 by my math.

 

[atoll]

That will make 4% h2O2 by my math.

Surely not if I had 50 mil of 12% peroxide and added 50mil of RO thats half so that woukd be 6% but I am adding twice as much 12% peroxide so it has to be more than 6% yes?

 

[Sashaka]

Decided to watch the debate going on before mixing. I think my confusion is catchy! Sorry guys!

 

[JonJ]

Surely not if I had 50 mil of 12% peroxide and added 50mil of RO thats half so that woukd be 6% but I am adding twice as much 12% peroxide so it has to be more than 6% yes?

Yes, you are correct. I read yours as 2 parts RO to 1 part 12% H2O2.

 

[Sashaka]

Ok guys, just so I understand what you great math gurus are saying...

Would that be...
16 x 2 = 32 and then 32/3 = 10.666% ? If so, I think I'm getting this...finally.

 

[JonJ]

If you are using 35% h2O2 then use this

 

[Sashaka]

If you are using 35% h2O2 then use this

Yes. I definitely will use the chart. I was just wondering about the math you and atoll were figuring out. If I understand the math behind the chart, I will be better able to adjust in between amounts if needed.

Right now...based on the chart...
I'm going to use 1 part 35% of H2O2 to 10 parts RODI water for 35/11 or 3.18% for the 34 gal nem tank with 1 catalyst in an Oxydator D.
For the 180 gal, I am going to try an oxydator A with two catalysts. I'm just not sure if I should add another oxydator A with one or two catalyst or a oxydator D with 1 or 2 catalyst. Would there be a difference?

Thanks again.

 

[Mortie31]

If you have 1L of 12% peroxide and add 0.5L of RO you have 1.5L of 8% mix
If you have 1L of peroxide and add 1L of RO you have 2L of 6% mix

 

[JonJ]

Yes. I definitely will use the chart. I was just wondering about the math you and atoll were figuring out. If I understand the math behind the chart, I will be better able to adjust in between amounts if needed.

Thanks again.

He is using a weaker H2O2 to start with meaning he has to use more parts H2O2 than water to get his desired %

For you and I, using 35% to start with means that we would always use more water than H2O2. So the math is original H2O2% divided by total parts (assuming 1 part H2O2) = diluted percentage.

Example would be if I started with 35% H2O2 and mixed it 1 to 5 parts water. That’s 6 total parts, so 35 divided 6 equals 5.83% (the new concentration).

Hope that helps!

 

[Sashaka]

He is using a weaker H2O2 to start with meaning he has to use more parts H2O2 than water to get his desired %

For you and I, using 35% to start with means that we would always use more water than H2O2. So the math is original H2O2% divided by total parts (assuming 1 part H2O2) = diluted percentage.

Example would be if I started with 35% H2O2 and mixed it 1 to 5 parts water. That’s 6 total parts, so 35 divided 6 equals 5.83% (the new concentration).

Hope that helps!

Yes. You confirmed the math that I got. Thanks!

 

[atoll]

Yes. I definitely will use the chart. I was just wondering about the math you and atoll were figuring out. If I understand the math behind the chart, I will be better able to adjust in between amounts if needed.

Right now...based on the chart...
I'm going to use 1 part 35% of H2O2 to 10 parts RODI water for 35/11 or 3.18% for the 34 gal nem tank with 1 catalyst in an Oxydator D.
For the 180 gal, I am going to try an oxydator A with two catalysts. I'm just not sure if I should add another oxydator A with one or two catalyst or a oxydator D with 1 or 2 catalyst. Would there be a difference?

Thanks again.

The main difference is down to how long each oxydator lasts between refills. However with stronger solutions of peroxide the peroxide in the model A is more likely to be converted/ broken down due to its design. With the model D you only have the catalysts and the base to act with the peroxide. With the model A the peroxide has the whole ceramic pot which also acts as a catalyst for any peroxide that escapes into it making it a safer and due to the amount it holds longer lasting between refills.