The posted picture says:
1 mL per 100 L boosts zinc by 10 ug/L
The DIY link I posted above (and which i corrected a typo in just now) says:
For the zinc sulfate, dissolve 1 gram of the solid material in 1 L of RO/DI. That solution contains 400 mg of zinc, so the concentration is 400 mg/L or 400 ug/mL.
Adding 1 mL to 100 L of tank water will boost aquarium zinc levels by 400 ug per 100 L or 4 ug/L.
Thus, that diy is somewhat less potent and adding 2.5 times as much as you do with the pictured bottle will match it.
Alternatively, if you dissolve 2.5 grams anhydrous zinc sulfate in a liter of RO/DI, it will match the pictured bottle in potency.
NOTE that this diy is for anhydrous zinc sulfate. If you have a hydrate or other ionic form of zinc, the numbers will change a bit.