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130 gallons is 492 liters.
You suggested an increase of 232 mg/L S.
That means 492 L x 232 mg/L = 114,000 mg or 114 g S.
Sodium sulfate (anhydrous mw = 142 g/mole) is 22.5% by weight S.
You thus need to add 114/.225 =507 g of sodium sulfate. I’d add that over a week.
Randy,130 gallons is 492 liters.
You suggested an increase of 232 mg/L S.
That means 492 L x 232 mg/L = 114,000 mg or 114 g S.
Sodium sulfate (anhydrous mw = 142 g/mole) is 22.5% by weight S.
You thus need to add 114/.225 =507 g of sodium sulfate. I’d add that over a week.
If you are using anhydrous sodium sulfate, that amount is well above the solubility limit of about 280 g/L. I would double or triple the amount of water, then dose 2 or 3 times as much.