Second New DIY Two Part Recipe with Higher pH Boost

[jeffp1]

There are many kinds that should be unaffected by pH, especially polyethylene tubing, but i would have though even normal airline tubing was pretty resistant.

This sort of table can help pick tubing:

Tubing Chemical Compatibility Tables
http://www.hollandapt.com/Documents...ng_Chemcial_Compatability_uid172010827381.pdf

Drop down to the listing for

Sodium hydroxide, 25%

On page 2. Many types show as OK, but some are not.

Thanks Randy

 

[Juano908]

Yes. CO2 will try to enter the alk part from the air, so keep it tightly closed. :)

Thanks again.

 

[Phillyd1990]

This might be a dumb question but can i use just the alk solution to help with ph and continue to use my current cal and mag (esv)

 

[Randy Holmes-Farley Verified Community Expert]

This might be a dumb question but can i use just the alk solution to help with ph and continue to use my current cal and mag (esv)

In general, yes. What brand of calcium?

 

[Phillyd1990]

In general, yes. What brand of calcium?

B ionic

 

[Randy Holmes-Farley Verified Community Expert]

That is an OK substitution until the ESV calcium runs out, but that calcium product is more potent than my DIY.

 

[Phillyd1990]

That is an OK substitution until the ESV calcium runs out, but that calcium product is more potent than my DIY.

Ok so best to just use the esv calcium chloride recipe with the alk recipe.

 

[Randy Holmes-Farley Verified Community Expert]

Ok so best to just use the esv calcium chloride recipe with the alk recipe.

Not sure what you mean, but expect to dose less of the ESV calcium than the DIY recipe alk part. It would no longer be 1:1.

 

[nanomania]

If i want to add strontium chloride in the cal/mag part, howmuch do i add? I know u dont support strontium, but i i want to add as iv been using seachem reef adv cal.

 

[Randy Holmes-Farley Verified Community Expert]

I discuss issues around determining how much strontium might be desirable to add to a recipe like this beginning here:

https://www.reef2reef.com/threads/n...h-higher-ph-boost.344500/page-10#post-4456604

 

[Tmmste]

If i want to add strontium chloride in the cal/mag part, howmuch do i add? I know u dont support strontium, but i i want to add as iv been using seachem reef adv cal.

If you are aiming for 1:50 mole ratio; if you use calcium chloride dehydrate 55,5gr would be 20 gr calcium / 40 gr ( = 1 mole calcium) which is 0.5 mole. 50% of this is 0,02 x 0,5 mole = x mole strontium. 1 mole of strontium is 87,62 gram. x mole x 87,62 = x gram strontium. x gram strontium / mass % (32,863%) = 2,6 gram of strontium chloride hexahydrate... this does not include the amount lost which the amount of water removed to compensate for the rise of salinity. Maybe this overview may help you out;

 

[nanomania]

If you are aiming for 1:50 mole ratio; if you use calcium chloride dehydrate 55,5gr would be 20 gr calcium / 40 gr ( = 1 mole calcium) which is 0.5 mole. 50% of this is 0,02 x 0,5 mole = x mole strontium. 1 mole of strontium is 87,62 gram. x mole x 87,62 = x gram strontium. x gram strontium / mass % (32,863%) = 2,6 gram of strontium chloride hexahydrate... this does not include the amount lost which the amount of water removed to compensate for the rise of salinity.

500 g of calcium chloride dihydrate plus 261.2 g of magnesium chloride hexahydrate and 8.3grams of strontium chloride in a total of 1 gallon..

THIS IS WHAT RANDY APPROVED IN THE OLDER 2part post.

 

[Tmmste]

500 g of calcium chloride dihydrate plus 261.2 g of magnesium chloride hexahydrate and 8.3grams of strontium chloride in a total of 1 gallon..

THIS IS WHAT RANDY APPROVED IN THE OLDER 2part post.

55.5 anhydrate = 73,5 dihydrate for 2.6gr strontium. 500 / 73.5 = a factor of 6.8 x 2.6 = 17.7 gr. This is identical to Balling & DSR Easy ratio for strontium. The ratio of randy is not 1:50 but more towards 1:100.

 

[nanomania]

55.5 anhydrate = 73,5 dihydrate for 2.6gr strontium. 500 / 73.5 = a factor of 6.8 x 2.6 = 17.7 gr. This is identical to Balling & DSR Easy ratio for strontium. The ratio of randy is not 1:50 but more towards 1:100.

Im confused, so do u add 2.6g or 17.7g? Instead of 8.3g

 

[nanomania]

Strontium chloride hexahydrate

 

[Randy Holmes-Farley Verified Community Expert]

My recommendation is here:

https://www.reef2reef.com/threads/n...h-higher-ph-boost.344500/page-10#post-4456604

8.3 grams of the strontium chloride hexahydrate per gallon. There's not going to be a perfect answer.

 

[Tmmste]

Im confused, so do u add 2.6g or 17.7g? Instead of 8.3g

Wel.. I will add a bit more than 2.6gr per 55.5gr (for dihydrate 2.6 per 73,5gr) as I will also compensate for the salinity correction. I am not going to exactly follow the new recipe as I am missing a lot of sulfate in the recipe to compensate for the amounts removed with the salinity correction.. (randy is this looking at this I think). I will probably do this (also including trace elements)

 

[Randy Holmes-Farley Verified Community Expert]

. I am not going to exactly follow the new recipe as I am missing a lot of sulfate in the recipe to compensate for the amounts removed with the salinity correction..

Can you clarify what that sentence means?

You add less sulfate to offset sulfate that is being lost in the salinity correction? That doesn't seem right, does it?

 

[Tmmste]

Can you clarify what that sentence means?

You add less sulfate to offset sulfate that is being lost in the salinity correction? That doesn't seem right, does it?

I will add much more sulfate. 37,52 gr per 40gr sodium hydroxide to be exact. This 37,52gr contains 8,47 gr of sulfate. which is 14% of the 60,54gr Chloride which is added by the stock solution. Around 3.1 L of aquariumwater is removed by the end of dosing this 1 liter of this stock (depends on the concentration but the principle remains the same). Apart from 60,54 chloride 35.15gr of sodium is added.. in total 95,7 gr of Sodium + chloride... 3.1l aquariumwater contains 30,5 x 3.1 = 95,7 gr of sodium & chloride.

There will be 3.1 l removed per 1l stock to keep salinity stable (again just to illustrate the calculation).. 3.1l contains;
3.1 x 2700 sulfate = 8,47 gr / 0,22574 = 37,52 gr of sodium sulfate. I believe this is accurate:

 

[Randy Holmes-Farley Verified Community Expert]

This will get very confusing since the sulfate discussion is now appended to a recipe thread that does not include sodium sulfate. I'll continue that discussion on the other thread.