Need no data just around 7 years in elementary school and knowledge of the metric system. If you have a solution of 100 ml with 12 % H2O2 based on volume - it means that 12 ml will be pure H2O2. Relative density of H2O2 is 34/18 = 1.88 - > it means that this 12 ml H2O2 has a weight of 1.88*12 = 22.56 g. Of this is H2O 18/34 = 0,529 .> 53 %. 47 % is extra O.
47 % of 22.56 g = 10,6 g O and with total conversion into O2 - it will form 5.3 g O2. 100 ml 12 % H2O2 will give 5.3 g O2 fully catalyzed. in 100 L - it means an extra boost of 53 mg/L O2 - in 1000 L it will boost the oxygen content with 5,3 mg/L. In my case - my oxidatorcatalyz 25 ml 12% H2O2 a day. - it means in best case around 1.33 g pure O2 a day. My aquarium is 300 L - it means an extra boost of 4.4 mg/L a day from only the oxydator ( . This has a huge impact on the average daily oxygen tension in an aquarium. In my aquarium - the 100 saturation is around 6.4 mg.
There is few studies done on oxygen levels in a reef aquarium. One that I know of says that the investigated aquarium had a saturation between 80% and around 120 % when a skimmer was in use (in my aquarium is should be between 5.1 to 7.7 mg/L depending on light or not. During my 12 dark hours - my oxydator would be able to deliver around 2.2 mg/L. My average oxygen tension would probably rise a lot but you are right in one thing. It should be nice to measure this up. I hope I will be able to do that in the future
By the way - I have always H2O2 at home. It is a reserve if I get a power shout down and no chance to oxygenate my water in other ways.
If I missed something in my math - please let me know
Sincerely Lasse
=